Advertisements
Advertisements
प्रश्न
Area of triangle PQR is 100 cm2 as shown in the below figure. If altitude QT is 10 cm, then its base PR is ______.
पर्याय
20 cm
15 cm
10 cm
5 cm
उत्तर
Area of triangle PQR is 100 cm2 as shown in the below figure. If altitude QT is 10 cm, then its base PR is 20 cm.
Explanation:
We know that, area of triangle = `1/2` × base × height
From the question, it is given that, area of triangle PQR = 100 cm2
Height of the triangle = 10 cm = altitude
Therefore, area of triangle = `1/2` × base × height
100 = `1/2` × PR × 10
PR = `(100 xx 2)/10`
PR = `200/10`
PR = 20 cm
APPEARS IN
संबंधित प्रश्न
Find the values of k so that the area of the triangle with vertices (1, -1), (-4, 2k) and (-k, -5) is 24 sq. units.
If the points A(−2, 1), B(a, b) and C(4, −1) are collinear and a − b = 1, find the values of a and b.
The coordinates of A, B, C are (6, 3), (–3, 5) and (4, – 2) respectively and P is any point (x, y). Show that the ratio of the areas of triangle PBC and ABC is
Find equation of line joining (3, 1) and (9, 3) using determinant.
Find the area of the following triangle:
ΔABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (see the given figure). The height AD from A to BC, is 6 cm. Find the area of ΔABC. What will be the height from C to AB i.e., CE?
Prove that the points (2a, 4a), (2a, 6a) and `(2a + sqrt3a, 5a)` are the vertices of an equilateral triangle.
Find the area of a triangle two sides of which are 18 cm and 10 cm and the perimeter is 42cm ?
The area of a triangle with vertices A(3, 0), B(7, 0) and C(8, 4) is ______.
If `D((-1)/2, 5/2), E(7, 3)` and `F(7/2, 7/2)` are the midpoints of sides of ∆ABC, find the area of the ∆ABC.