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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

At room temperature (27.0°C) the resistance of a heating element is 100 Ω. What is the temperature of the element if the resistance is found to be 117 Ω, given that the temperature coefficient of the - Physics

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प्रश्न

At room temperature (27.0°C) the resistance of a heating element is 100 Ω. What is the temperature of the element if the resistance is found to be 117 Ω, given that the temperature coefficient of the material of the resistor is 1.70 × 10−4 °C−1.

संख्यात्मक

उत्तर

Room temperature, T = 27°C

Resistance of the heating element at T, R = 100 Ω

Let T1 is the increased temperature of the filament.

Resistance of the heating element at T1, R1 = 117 Ω

Temperature co-efficient of the material of the filament,

α = 1.70 × 10−4 °C−1

α is given by the relation 

α = `("R"_1 - "R")/("R"("T"_1 - "T"))`

`"T"_1 - "T" = ("R"_1 - "R")/("R"α)`

`"T"_1 - 27 = (117 - 100)/(100(1.7 xx 10^-4))`

`"T"_1 - 27 = 1000`

T1 = 1027°C

Therefore, at 1027°C, the resistance of the element is 117 Ω.

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Temperature Dependence of Resistance
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पाठ 3: Current Electricity - Exercise [पृष्ठ १२७]

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एनसीईआरटी Physics [English] Class 12
पाठ 3 Current Electricity
Exercise | Q 3.5 | पृष्ठ १२७
एनसीईआरटी Physics [English] Class 12
पाठ 3 Current Electricity
Exercise | Q 5 | पृष्ठ १२७

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