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प्रश्न
Choose the correct alternative:
Let the function f be defined by `f(x) = {{:(3x, 0 ≤ x ≤ 1),(-3 + 5, 1 < x ≤ 2):}`, then
पर्याय
`lim_(x -> 1) f(x)` = 1
`lim_(x -> 1) f(x)` = 3
`lim_(x -> 1) f(x)` = 2
`lim_(x -> 1) f(x)` does not exist
उत्तर
`lim_(x -> 1) f(x)` does not exist
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