मराठी

Describe Completely the Locus of Point in the Following Cases: - Mathematics

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प्रश्न

Describe completely the locus of point in the following cases: 

Centre of a ball, rolling along a straight line on a level floor. 

आकृती

उत्तर

The locus of the centre of a ball, rolling along a straight line on a level floor will be a straight Iine paralIel to the floor at a di stance equal to the radius of the ball.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 16: Loci - Exercise 16.1

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संबंधित प्रश्‍न

Angle ABC = 60° and BA = BC = 8 cm. The mid-points of BA and BC are M and N respectively. Draw and describe the locus of a point which is:

  1. equidistant from BA and BC.
  2. 4 cm from M.
  3. 4 cm from N.
    Mark the point P, which is 4 cm from both M and N, and equidistant from BA and BC. Join MP and NP, and describe the figure BMPN.

Draw an angle ABC = 75°. Find a point P such that P is at a distance of 2 cm from AB and 1.5 cm from BC.


Construct a rhombus ABCD whose diagonals AC and BD are 8 cm and 6 cm respectively. Find by construction a point P equidistant from AB and AD and also from C and D. 


Construct a ti.PQR, in which PQ=S. 5 cm, QR=3. 2 cm and PR=4.8 cm. Draw the locus of a point which moves so that it is always 2.5 cm from Q. 


A and B are fixed points while Pis a moving point, moving in a way that it is always equidistant from A and B. What is the locus of the path traced out by the pcint P? 


Describe completely the locus of point in  the following cases: 

Midpoint of radii of a circle. 


Describe completely the locus of points in the following cases: 

Point in a plane equidistant from a given line. 


Describe completely the locus of points in the following cases: 

Centre of a circle of varying radius and touching the two arms of ∠ ABC. 


Describe completely the locus of points in the following cases: 

Centre of a cirde of radius 2 cm and touching a fixed circle of radius 3 cm with centre O. 


Using a ruler and compass only: 
(i) Construct a triangle ABC with BC = 6 cm, ∠ABC = 120° and AB = 3.5 cm.
(ii) In the above figure, draw a circle with BC as diameter. Find a point 'P' on the circumference of the circle which is equidistant from Ab and BC.
Measure ∠BCP.


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