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प्रश्न
Evaluate the following limit :
`lim_(x -> -3)[(x + 3)/(x^2 + 4x + 3)]`
उत्तर
`lim_(x -> -3)[(x + 3)/(x^2 + 4x + 3)]`
= `lim_(x -> - 3) (x + 3)/((x + 3)(x + 1)`
= `lim_(x -> - 3) 1/(x + 1) ...[(because x -> - 3"," therefore x ≠ - 3","),(therefore x + 3 ≠ 0)]`
= `1/(-3 + 1)`
= `-1/2`
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