Advertisements
Advertisements
प्रश्न
Evaluate the following: sec16° tan28° - cot62° cosec74°
उत्तर
sec16° tan28° - cot62° cosec74°
= sec(90° - 74°)tan(90° - 62°) - cot62° cosec74°
= cosec74° cot62° - cot62° cosec74°
= 0
APPEARS IN
संबंधित प्रश्न
Solve for x : 2 cos (3x - 15°) = 1
Find the value of 'A', if cosec 3A = `(2)/sqrt(3)`
If θ = 30°, verify that: sin2θ = `(2tanθ)/(1 ++ tan^2θ)`
Find the value 'x', if:
Evaluate the following: `(sin62°)/(cos28°)`
Evaluate the following: `(tan42°)/(cot48°) + (cos33°)/(sin57°)`
Evaluate the following: `(2sin28°)/(cos62°) + (3cot49°)/(tan41°)`
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos84° + cosec69° - cot68°
Evaluate the following: `(2sin25° sin35° sec55° sec65°)/(5tan 29° tan45° tan61°) + (3cos20° cos50° cot70° cot40°)/(5tan20° tan50° sin70° sin40°)`
If cos3θ = sin(θ - 34°), find the value of θ if 3θ is an acute angle.
