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प्रश्न
Factorise:
6x2 + 7x – 3
उत्तर
6x2 + 7x – 3
= 6x2 + 9x – 2x – 3
= 3x(2x + 3) – 1(2x + 3) ...[By splitting middle term]
= (3x – 1)(2x + 3)
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संबंधित प्रश्न
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = 2x3 + x2 – 2x – 1, g(x) = x + 1
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p(x) = x3 + 3x2 + 3x + 1, g(x) = x + 2
Factorise:
x3 – 2x2 – x + 2
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2y3 + y2 – 2y – 1
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(x2 – 6x)2 – 8 (x2 – 6x + 8) – 64
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3x2 + 6x – 24
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Factorise the following:
9x2 – 12x + 4
Find the following product:
(2x – y + 3z)(4x2 + y2 + 9z2 + 2xy + 3yz – 6xz)
Without finding the cubes, factorise:
(x – 2y)3 + (2y – 3z)3 + (3z – x)3
