Advertisements
Advertisements
प्रश्न
Factorize the following polynomial.
(x2 – 6x)2 – 8 (x2 – 6x + 8) – 64
उत्तर
(x2 – 6x)2 – 8 (x2 – 6x + 8) – 64
= (x2 – 6x)2 – 8(x2 – 6x) – 64 – 64
= (x2 – 6x)2 – 8(x2 – 6x) – 128
Let x2 – 6x = z.
∴ (x2 – 6x)2 – 8(x2 – 6x) – 128
= z2 – 8z – 128
= z2 – 16 z + 8z – 128
= z(z – 16) + 8 (z – 16)
= (z – 16) (z +8)
= (x2 – 6x – 16) (x2 – 6x + 8) ...(Replace z = x2 – 6x)
= (x2 – 8x + 2x – 16) (x2 – 4x – 2x + 8)
= [x (x – 8) + 2 (x – 8)] [x (x – 4) – 2 (x – 4)]
= (x – 8) (x + 2) (x – 4) (x – 2)
APPEARS IN
संबंधित प्रश्न
Factorise:
2x2 + 7x + 3
Factorise:
6x2 + 5x – 6
Find the Factors of the Polynomial Given Below.
2x2 + x – 1
Find the factor of the polynomial given below.
2m2 + 5m – 3
Find the factor of the polynomial given below.
`sqrt 3 x^2 + 4x + sqrt 3`
Factorize the following polynomial.
(x2 – x)2 – 8 (x2 – x) + 12
One of the factors of (25x2 – 1) + (1 + 5x)2 is ______.
Show that 2x – 3 is a factor of x + 2x3 – 9x2 + 12.
Factorise:
`a^3 - 2sqrt(2)b^3`
Factorise:
`2sqrt(2)a^3 + 8b^3 - 27c^3 + 18sqrt(2)abc`
