Advertisements
Advertisements
प्रश्न
Find the angle measure x in the given Figure
उत्तर
From the figure, it can be concluded that,
70 + a = 180° (Linear pair)
a = 110°
60° + b = 180° (Linear pair)
b = 120°
Sum of the measures of all interior angles of a pentagon is 540º.
Therefore, in the given pentagon,
120° + 110° + 30° + x + x = 540°
260° + 2x = 540°
2x = 280°
x = 140°
APPEARS IN
संबंधित प्रश्न
Find the angle measure x in the given Figure
Find x in the following figures.
Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle
In Fig. below, ABCD is a parallelogram in which ∠DAB = 75° and ∠DBC = 60°. Compute
∠CDB and ∠ADB.
If PQRS is a square, then write the measure of ∠SRP.
In a quadrilateral ABCD, bisectors of angles A and B intersect at O such that ∠AOB = 75°, then write the value of ∠C + ∠D.
If the degree measures of the angles of quadrilateral are 4x, 7x, 9x and 10x, what is the sum of the measures of the smallest angle and largest angle?
All the angles of a quadrilateral are equal. What special name is given to this quadrilateral?
The angle between two altitudes of a parallelogram through the vertex of an obtuse angle of the parallelogram is 60º. Find the angles of the parallelogram.
The polygon in which sum of all exterior angles is equal to the sum of interior angles is called ______.