Advertisements
Advertisements
प्रश्न
Find the area of a triangle whose sides are 3 cm, 4 cm and 5 cm respectively.
उत्तर
The area of a triangle having sides a, b, c and s as semi-perimeter is given by,
`A = sqrt( s(s-a)(s-b)(s-c)`, where
`s = (a+b+c)/2`
Therefore the area of a triangle, say having sides 3 cm, 4 cm and 5 cm is given by
a = 3 cm ; b = 4 cm ; c = 5 cm
`s = (a+b+c)/2`
`s = (3+4+5)/2`
`s =12/2`
s = 6 cm Now, area `A = sqrt(s(s-a)(s-b)(s-c)`
\[= \sqrt{6(6 - 3)(6 - 4)(6 - 5)}\]
\[ = \sqrt{6 \times 3 \times 2 \times 1}\]
\[ = \sqrt{36}\]
\[ = 6 c m^2\]
APPEARS IN
संबंधित प्रश्न
The perimeter of a triangle is 300 m. If its sides are in the ratio 3 : 5 : 7. Find the area of the triangle ?
The perimeter of an isosceles triangle is 42 cm and its baše is (32) times each of the equal sides. Find the length of each side of the triangle, area of the triangle and the height of the triangle.
Find the area of the shaded region in the given figure.
Find the area of a quadrilateral ABCD in which AB = 42 cm, BC = 21 cm, CD = 29 cm, DA =34 cm and diagonal BD =20 cm.
Find the area of the triangle formed by the points
(1, – 1), (– 4, 6) and (– 3, – 5)
A triangular shaped glass with vertices at A(– 5, – 4), B(1, 6) and C(7, – 4) has to be painted. If one bucket of paint covers 6 square feet, how many buckets of paint will be required to paint the whole glass, if only one coat of paint is applied
The area of a triangle is 5 sq. units. Two of its vertices are (2, 1) and (3, −2). The third vertex is (x, y) where y = x + 3. Find the coordinates of the third vertex.
Using Heron’s formula, find the area of a triangle whose sides are 1.8 m, 8 m, 8.2 m
A field in the form of a parallelogram has sides 60 m and 40 m and one of its diagonals is 80 m long. Find the area of the parallelogram.
The sides of a quadrilateral ABCD are 6 cm, 8 cm, 12 cm and 14 cm (taken in order) respectively, and the angle between the first two sides is a right angle. Find its area.
