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प्रश्न
Find the equation of the line parallel to y-axis and drawn through the point of intersection of the lines x– 7y + 5 = 0 and 3x + y = 0.
उत्तर
Given lines
x – 7y + 5 = 0 …(i)
3x + y = 0 ... (ii)
From equation (ii),
y = -3x
Putting the value of y in equation (i),
x – 7(−3x) + 5 = 0
or 22x + 5 = 0
x = `(-5)/22`
Now y = -3x = `-3((-5)/22)`
= `15/22`
The equation of the line that passes through `((- 5)/22, 15/22)` and is parallel to the y-axis is x = `(- 5)/22`
or 22x + 5 = 0
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| (a) Parallel to y-axis is | (i) λ = `-3/4` |
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| (d) Parallel to x axis is | λ = 3 |
