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प्रश्न
Find the G.C.D. of the given polynomials
x4 – 1, x3 – 11x2 + x – 11
उत्तर
p(x) = x4 – 1
g(x) = x3 – 11x2 + x – 11
120x2 + 120 = 120(x2 + 1)
Now dividing g(x) = x3 – 11x2 + x – 11 by the new remainder (leaving the constant) we get x2 + 1
G.C.D. = x2 + 1
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