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प्रश्न
Find the rectangular form of the complex numbers
`(cos pi/6 - "i" sin pi/6)/(2(cos pi/3 + "i" sin pi/3))`
उत्तर
`(cos pi/6 - "i" sin pi/6)/(2(cos pi/3 + "i" sin pi/3)) = 1/2 (cos((-pi)/6) + "i"sin((-pi)/6))/(cos pi/3 + "i"sin(pi/3))`
= `1/2 cos((-pi)/6 - pi/3) + "i"sin((-pi)/6 - pi/3)`
= `1/2[cos((-pi)/2) + "i"sin((-pi)/2)]`
= `1/2[cos(pi/2) + "i"sin(pi/2)]`
= `1/2[- "i"]`
= `0 - "i"/2`
= `- "i"/2`
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