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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता ९

Find the remainder when 3x3 – 4x2 + 7x – 5 is divided by (x + 3) - Mathematics

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प्रश्न

Find the remainder when 3x3 – 4x2 + 7x – 5 is divided by (x + 3)

बेरीज

उत्तर

p(x) = 3x3 – 4x2 + 7x – 5

When it is divided by x + 3,

p(–3) = 3(–3)3 – 4(–3)2 + 7(–3) – 5

= 3(–27) – 4(9) – 21 – 5

= – 81 – 36 – 21 – 5

= –143

The remainder is –143.

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पाठ 3: Algebra - Exercise 3.3 [पृष्ठ ९६]

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सामाचीर कलवी Mathematics [English] Class 9 TN Board
पाठ 3 Algebra
Exercise 3.3 | Q 3 | पृष्ठ ९६
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