Advertisements
Advertisements
प्रश्न
What is the remainder when x2018 + 2018 is divided by x – 1
उत्तर
p(x) = x2018 + 2018
When it is divided by x – 1,
p(1) = 12018 + 2018
= 1 + 2018
= 2019
The remainder is 2019.
APPEARS IN
संबंधित प्रश्न
Using the Remainder and Factor Theorem, factorise the following polynomial:
`x^3 + 10x^2 - 37x + 26`
Using the Remainder Theorem, factorise the following completely:
3x3 + 2x2 – 23x – 30
Using the Remainder Theorem, factorise the expression 3x3 + 10x2 + x – 6. Hence, solve the equation 3x3 + 10x2 + x – 6 = 0
Find without division, the remainder in the following:
5x3 - 7x2 +3 is divided by (x-1)
Find the values of a and b when the polynomial f(x)= ax3 + 3x2 +bx -3 is exactly divisible by (2x+3) and leaves a remainder -3 when divided by (x+2).
Use the Remainder Theorem to factorise the following expression:
2x3 + x2 – 13x + 6
If on dividing 2x3 + 6x2 – (2k – 7)x + 5 by x + 3, the remainder is k – 1 then the value of k is
If x + 1 is a factor of 3x3 + kx2 + 7x + 4, then the value of k is
For what value of m is x3 – 2mx2 + 16 divisible by x + 2?
If the polynomials az3 + 4z2 + 3z – 4 and z3 – 4z + a leave the same remainder when divided by z – 3, find the value of a.
