Advertisements
Advertisements
प्रश्न
Find the unknown marked angles in the given figure:
उत्तर
In the figure,
∠A + ∠B + ∠C = 180° .....(Sum of angles of a triangle)
x° + 90° + x° = 180°
⇒ 2x°+ 90° = 180°
⇒ 2x° = 180° − 90°
⇒ 2x°= 90°
⇒ x° = `(90° )/2=45° `
Hence ∠A = x° = 45°
and ∠C = x° = 45°
APPEARS IN
संबंधित प्रश्न
In Δ ABC, BD⊥ AC and CE ⊥ AB. If BD and CE intersect at O, prove that ∠BOC = 180° − A.
The sum of two angles of a triangle is equal to its third angle. Determine the measure of the third angle.
If the side BC of ΔABC is produced on both sides, then write the difference between the sum of the exterior angles so formed and ∠A.
An exterior angle of a triangle is equal to 100° and two interior opposite angles are equal. Each of these angles is equal to
In ΔRST (See figure), what is the value of x?
In a triangle PQR, ∠P = 60° and ∠Q = ∠R, find ∠R.
One of the base angles of an isosceles triangle is 52°. Find its angle of the vertex.
Can a triangle together have the following angles?
55°, 55° and 80°
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
8.4 cm, 16.4 cm, 4.9 cm
If an angle of a triangle is equal to the sum of the other two angles, find the type of the triangle