Advertisements
Advertisements
प्रश्न
Find, which of the following points lie on the line x – 2y + 5 = 0 :
(–5, 0)
उत्तर
The given line is x − 2y + 5 = 0.
Substituting x = −5 and y = 0 in the given equation, we have:
L.H.S. = −5 − 2 × 0 + 5
= −5 − 0 + 5
= 5 − 5
= 0 = R.H.S.
Thus, the point (−5, 0) lie on the given line.
APPEARS IN
संबंधित प्रश्न
The co-ordinates of two points A and B are (-3, 4) and (2, -1) Find: the co-ordinates of the point where the line AB intersects the y-axis.
Find the equations of the line through (1, 3) and making an intercept of 5 on the y-axis.
The given figure (not drawn to scale) shows two straight lines AB and CD. If equation of the line AB is : y = x + 1 and equation of line CD is : y = `sqrt(3)x - 1`. Write down the inclination of lines AB and CD; also, find the angle θ between AB and CD.
Find if the following points lie on the given line or not:
(7, -2) on the line 5x + 7y = 11
The line y = 6- `(3"x")/2` passes through the point (r,3). Find the value of r.
ABCD is rhombus. The coordinates of A and C ae (3,7) and (9,15). Find the equation of BD.
Find the equation of a line passing through the intersection of x + 3y = 6 and 2x - 3y = 12 and parallel to the line 5x + 2y = 10
PQ is straight line of 13 units. If P has coordinate (2, 5) and Q has coordinate (x, – 7) find the possible values of x.
Find the equation of a straight line which cuts an intercept of 5 units on Y-axis and is parallel to the line joining the points (3, – 2) and (1, 4).
Given equation of line L1 is y = 4.
(i) Write the slope of line, if L2 is the bisector of angle O.
(ii) Write the coordinates of point P.
(iii) Find the equation of L2
