Advertisements
Advertisements
प्रश्न
Find without division, the remainder in the following:
8x2 - 2x + 1 is divided by (2x+ 1)
उत्तर
8x2 - 2x + 1 is divided by (2x+ 1)
Putting 2x + 1 = 0, we get : x=-`1/2`
Substituting this value of x in the equation, we get
`8 xx (-1/2) xx (-1/2) - 2 xx (-1/2) + 1`
= 2 + 1 + 1
= 4
APPEARS IN
संबंधित प्रश्न
Using remainder theorem, find the value of k if on dividing 2x3 + 3x2 – kx + 5 by x – 2, leaves a remainder 7.
Use Remainder theorem to factorize the following polynomial:
`2x^3 + 3x^2 - 9x - 10`
If (x – 2) is a factor of the expression 2x3 + ax2 + bx – 14 and when the expression is divided by (x – 3), it leaves a remainder 52, find the values of a and b.
The polynomials ax3 + 3x2 – 3 and 2x3 – 5x + a, when divided by x – 4, leave the same remainder in each case. Find the value of a.
use the rernainder theorem to find the factors of ( a-b )3 + (b-c )3 + ( c-a)3
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 4x2 + 5x + 3
What number must be subtracted from 2x2 – 5x so that the resulting polynomial leaves the remainder 2, when divided by 2x + 1 ?
If on dividing 2x3 + 6x2 – (2k – 7)x + 5 by x + 3, the remainder is k – 1 then the value of k is
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x3 – 2x2 – 4x – 1, g(x) = x + 1
The polynomial p(x) = x4 – 2x3 + 3x2 – ax + 3a – 7 when divided by x + 1 leaves the remainder 19. Find the values of a. Also find the remainder when p(x) is divided by x + 2.