Advertisements
Advertisements
प्रश्न
If ΔABC ~ ΔDEF such that AB = 5 cm, area (ΔABC) = 20 cm2 and area (ΔDEF) = 45 cm2, determine DE.
उत्तर
We have,
ΔABC ~ ΔDEF such that AB = 5 cm,
Area (ΔABC) = 20 cm2 and area(ΔDEF) = 45 cm2
By area of similar triangle theorem
`("Area"(triangleABC))/("Area"(triangleDEF))="AB"^2/"DE"^2`
`rArr20/45=5^2/"DE"^2`
`rArr4/9=5^2/"DE"^2`
`rArr2/3=5/"DE"` [Taking square root]
`rArr"DE"=(3xx5)/2=7.5` cm
APPEARS IN
संबंधित प्रश्न
D, E, F are the mid-point of the sides BC, CA and AB respectively of a ∆ABC. Determine the ratio of the areas of ∆DEF and ∆ABC.
In Figure, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that `(ar(ABC))/(ar(DBC)) = (AO)/(DO)`
Triangles ABC and DEF are similar If AC = 19cm and DF = 8 cm, find the ratio of the area of two triangles.
Two isosceles triangles have equal vertical angles and their areas are in the ratio 36 : 25. Find the ratio of their corresponding heights.
The areas of two similar triangles are 121 cm2 and 64 cm2 respectively. If the median of the first triangle is 12.1 cm, find the corresponding median of the other.
AD is an altitude of an equilateral triangle ABC. On AD as base, another equilateral triangle ADE is constructed. Prove that Area (ΔADE): Area (ΔABC) = 3: 4
Areas of two similar triangles are 225 sq.cm. 81 sq.cm. If a side of the smaller triangle is 12 cm, then Find corresponding side of the bigger triangle.
O is a point on side PQ of a APQR such that PO = QO = RO, then ______.
In a rectangle Length = 8 cm, Breadth = 6 cm. Then its diagonal = ______.
If ΔABC ∼ ∆PQR and AB : PQ = 2 : 3, then find the value of `(A(triangleABC))/(A(trianglePQR))`.
