Advertisements
Advertisements
प्रश्न
Triangles ABC and DEF are similar If AC = 19cm and DF = 8 cm, find the ratio of the area of two triangles.
उत्तर
We have,
ΔABC ~ ΔDEF
AC = 19 cm and DF = 8 cm
By area of similar triangle theorem
`("Area"(triangleABC))/(Area(triangleDEF))="AC"^2/"DF"^2=19^2/8^2=361/64`
APPEARS IN
संबंधित प्रश्न
Prove that the area of the triangle BCE described on one side BC of a square ABCD as base is one half the area of the similar Triangle ACF described on the diagonal AC as base
ABC and BDE are two equilateral triangles such that D is the mid-point of BC. Ratio of the area of triangles ABC and BDE is
Triangles ABC and DEF are similar If area (ΔABC) = 36 cm2, area (ΔDEF) = 64 cm2 and DE = 6.2 cm, find AB.
ABC is a triangle in which ∠A =90°, AN⊥ BC, BC = 12 cm and AC = 5cm. Find the ratio of the areas of ΔANC and ΔABC.
The areas of two similar triangles are 121 cm2 and 64 cm2 respectively. If the median of the first triangle is 12.1 cm, find the corresponding median of the other.
Areas of two similar triangles are 225 sq.cm. 81 sq.cm. If a side of the smaller triangle is 12 cm, then Find corresponding side of the bigger triangle.
∆MNT ~ ∆QRS. Length of altitude drawn from point T is 5 and length of altitude drawn from point S is 9. Find the ratio `("A"(Δ"MNT"))/("A"(Δ"QRS"))`.
If ∆XYZ ~ ∆PQR and A(∆XYZ) = 25 cm2, A(∆PQR) = 4 cm2 then XY : PQ = ?
If ΔABC ~ ΔPQR, AB : PQ = 4 : 5 and A(ΔPQR) = 125 cm2, then find A(ΔABC).
If ΔABC ∼ ∆PQR and AB : PQ = 2 : 3, then find the value of `(A(triangleABC))/(A(trianglePQR))`.
