Advertisements
Advertisements
प्रश्न
Triangles ABC and DEF are similar If AC = 19cm and DF = 8 cm, find the ratio of the area of two triangles.
उत्तर
We have,
ΔABC ~ ΔDEF
AC = 19 cm and DF = 8 cm
By area of similar triangle theorem
`("Area"(triangleABC))/(Area(triangleDEF))="AC"^2/"DF"^2=19^2/8^2=361/64`
APPEARS IN
संबंधित प्रश्न
In a trapezium ABCD, O is the point of intersection of AC and BD, AB || CD and AB = 2 × CD. If the area of ∆AOB = 84 cm2 . Find the area of ∆COD
Sides of two similar triangles are in the ratio 4 : 9. Areas of these triangles are in the ratio
If D is a point on the side AB of ΔABC such that AD : DB = 3.2 and E is a Point on BC such that DE || AC. Find the ratio of areas of ΔABC and ΔBDE.
If ΔABC and ΔBDE are equilateral triangles, where D is the mid-point of BC, find the ratio of areas of ΔABC and ΔBDE.
In ΔABC, PQ is a line segment intersecting AB at P and AC at Q such that seg PQ || seg BC. If PQ divides ΔABC into two equal parts having equal areas, find `"BP"/"AB"`.
If ∆ABC ~ ∆PQR and AB : PQ = 3 : 4 then A(∆ABC) : A(∆PQR) = ?
In the adjoining figure, ΔADB ∼ ΔBDC. Prove that BD2 = AD × DC.
If ΔABC ∼ ΔPQR and `(A(ΔABC))/(A(ΔPQR)) = 16/25`, then find AB : PQ.
If ΔPQR ∼ ΔABC; PQ = 6 cm, AB = 8 cm and the perimeter of ΔABC is 36 cm, then the perimeter of ΔPQR is ______.
If ΔABC ∼ ∆PQR and AB : PQ = 2 : 3, then find the value of `(A(triangleABC))/(A(trianglePQR))`.