मराठी

If x cos θ = ycos(θ+2π3)=zcos(θ+4π3), then find the value of xy + yz + zx. - Mathematics

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प्रश्न

If x cos θ = `y cos (theta + (2pi)/3) = z cos (theta + (4pi)/3)`, then find the value of xy + yz + zx.

बेरीज

उत्तर

Note that xy + yz + zx = `xyz (1/x + 1/y + 1/z)`.

If we put x cos θ = `y cos (theta + (2pi)/3)`

= `z cos (theta + (4pi)/3)` = k  ...(say)

Then x = `k/costheta`, y = `k/(cos(theta + (2pi)/3)` and z = `k/(cos(theta + (4pi)/3)`

So that `1/x + 1/y + 1/z = 1/"k"[cos theta + cos(theta + (2pi)/3) + cos(theta + (4pi)/3)]`

= `1/k [costheta + costheta cos  (2pi)/3 - sin theta sin  (2pi)/3 + cos theta cos  (4pi)/3 - sin theta sin  (4pi)/3]`

= `1/k[cos theta + cos theta ((-1)/2) - sqrt(3)/2 sin theta - 1/2 cos theta + sqrt(3)/2 sin theta]` 

= `1/k xx 0`

= 0

Hence, xy + yz + zx = 0

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Sine and Cosine Formulae and Their Applications
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पाठ 3: Trigonometric Functions - Solved Examples [पृष्ठ ४३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
पाठ 3 Trigonometric Functions
Solved Examples | Q 10 | पृष्ठ ४३

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