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प्रश्न
If z = 2 – 2i, find the rotation of z by θ radians in the counterclockwise direction about the origin when θ = `(3pi)/3`
उत्तर
θ = `(3pi)/3`
∴ Argument = `(3pi)/2 - pi/4`
= `(5pi)/4`
∴ New position is `2sqrt(2) (cos (5pi)/4 + "i" sin (5pi)/4)`
= `2sqrt(2) "e"^((15pi)/4)`
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