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प्रश्न
In the following figure, in Δ PQR, seg RS is the bisector of ∠PRQ.
PS = 11, SQ = 12, PR = 22. Find QR.
उत्तर
SR is the bisector of ∠R.
`"RP"/"PS"="QR"/"SQ"`
`rArr22/11="QR"/12`
`therefore"QR"=24"cm"`
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