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प्रश्न
In the given figure:
(i) If ∠AOB = 45°, ∠BOC = 30° and ∠AOD= 110°; find : angles COD and BOD.
(ii) If ∠BOC = ∠DOC = 34° and ∠AOD = 120° ; find : angle AOB and angle AOC.
(iii) If ∠AOB = ∠BOC = ∠COD = 38° find : reflex angle AOC and reflex angle AOD.
उत्तर
(i) ∠COD = ∠AOD – ∠AOC
= ∠AOD – (∠AOB + ∠BOC)
= 110° - (45°+ 30°)
= 110°- 75°
= 35°
∠BOD = ∠AOD -∠AOB
= 110° - 45°
= 65°
(ii) ∠AOB = ∠AOD-∠BOD
= ∠AOD – (∠BOC + ∠COD)
= 120° – (34° + 34°)
= 120°-68°
= 52°
∠AOC = ∠AOB + ∠BOC
= 52° + 34°
= 86°
(iii) Reflex ∠AOC = 360°-∠AOC
= 360° – (∠AOB + ∠BOC)
= 360° – (38° + 38°)
= 360° – 76° = 284°
Reflex ∠AOD = 360° – ∠AOD
= 360° (∠AOB + ∠BOC + ∠COD)
= 360° – (38° + 38° + 38°)
= 360°- 114°
= 246°
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