Advertisements
Advertisements
प्रश्न
KM is a straight line of 13 units If K has the coordinate (2, 5) and M has the coordinates (x, – 7) find the possible value of x.
उत्तर
Using distance formula
(x2 - x1)2 + (y2 - y1)2 = d2
⇒ (x - 2)2 + (-7 - 5)2 = 132
⇒ x2 - 4x + 4 + 144 = 169
⇒ x2 - 4x + 148 - 169 = 0
⇒ x2 - 4x - 21 = 0
⇒ x2 - 7x + 3x - 21 = 0
⇒ (x - 7) +3 (x - 7) = 0
⇒ (x + 3) (x - 7) = 0
x = 7, -3.
APPEARS IN
संबंधित प्रश्न
If P and Q are two points whose coordinates are (at2 ,2at) and (a/t2 , 2a/t) respectively and S is the point (a, 0). Show that `\frac{1}{SP}+\frac{1}{SQ}` is independent of t.
Find the distance between the following pairs of points:
(2, 3), (4, 1)
Find the point on the x-axis which is equidistant from (2, -5) and (-2, 9).
Find the distance of the following points from the origin:
(i) A(5,- 12)
For what values of k are the points (8, 1), (3, –2k) and (k, –5) collinear ?
Find the distances between the following point.
P(–6, –3), Q(–1, 9)
Find the relation between x and y if the point M (x,y) is equidistant from R (0,9) and T (14 , 11).
A line segment of length 10 units has one end at A (-4 , 3). If the ordinate of te othyer end B is 9 , find the abscissa of this end.
Given A = (3, 1) and B = (0, y - 1). Find y if AB = 5.
What is the distance of the point (– 5, 4) from the origin?
