Advertisements
Advertisements
प्रश्न
What is the distance of the point (– 5, 4) from the origin?
पर्याय
3 units
`sqrt(14)` units
`sqrt(31)` units
`sqrt(41)` units
उत्तर
`sqrt(41)` units
Explanation:
Given points are (– 5, 4) and (0, 0).
Distance = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
Here, x1 = – 5, y1 = 4, x2 = 0, y2 = 0
∴ Distance = `sqrt((0 - (- 5))^2 + (0 - 4)^2`
= `sqrt(5^2 + 4^2)`
= `sqrt(25 + 16)`
= `sqrt(41)`
Thus, the distance is `sqrt(41)` units.
APPEARS IN
संबंधित प्रश्न
If the point P(2, 2) is equidistant from the points A(−2, k) and B(−2k, −3), find k. Also find the length of AP.
Find the coordinates of the circumcentre of the triangle whose vertices are (8, 6), (8, – 2) and (2, – 2). Also, find its circum radius
Find the point on the x-axis which is equidistant from (2, -5) and (-2, 9).
A(–8, 0), B(0, 16) and C(0, 0) are the vertices of a triangle ABC. Point P lies on AB and Q lies on AC such that AP : PB = 3 : 5 and AQ : QC = 3 : 5. Show that : PQ = `3/8` BC.
Find the distance between the points
(ii) A(7,-4)and B(-5,1)
Determine whether the points are collinear.
L(–2, 3), M(1, –3), N(5, 4)
Distance of point (-3, 4) from the origin is .....
(A) 7 (B) 1 (C) 5 (D) 4
Find the distance between the following pairs of point in the coordinate plane :
(13 , 7) and (4 , -5)
Find the distance of the following point from the origin :
(6 , 8)
Find the distance of the following point from the origin :
(13 , 0)
Find the coordinates of O, the centre passing through A( -2, -3), B(-1, 0) and C(7, 6). Also, find its radius.
A point A is at a distance of `sqrt(10)` unit from the point (4, 3). Find the co-ordinates of point A, if its ordinate is twice its abscissa.
A point P lies on the x-axis and another point Q lies on the y-axis.
Write the abscissa of point Q.
Find the distance of the following points from origin.
(a+b, a-b)
Find distance between points O(0, 0) and B(– 5, 12)
Find distance between point A(–1, 1) and point B(5, –7):
Solution: Suppose A(x1, y1) and B(x2, y2)
x1 = –1, y1 = 1 and x2 = 5, y2 = – 7
Using distance formula,
d(A, B) = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
∴ d(A, B) = `sqrt(square +[(-7) + square]^2`
∴ d(A, B) = `sqrt(square)`
∴ d(A, B) = `square`
A circle drawn with origin as the centre passes through `(13/2, 0)`. The point which does not lie in the interior of the circle is ______.
The point A(2, 7) lies on the perpendicular bisector of line segment joining the points P(6, 5) and Q(0, – 4).
The points A(–1, –2), B(4, 3), C(2, 5) and D(–3, 0) in that order form a rectangle.