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प्रश्न
Find the coordinates of O, the centre passing through A( -2, -3), B(-1, 0) and C(7, 6). Also, find its radius.
उत्तर
let o (x, y) be the centre of the circle.
OA = OB (radii of square circle)
⇒ OA2 = OB2
(x + 2)2 + (y + 3)2 = (x + 1)2 + (y - 0)2
⇒ x2 + 4 + 4x + y2 + 9 + 6y = x2 + 1 + 2x + y2
⇒ 2x + 6y + 12 = 0
⇒ x + 3y + 6 = 0 .........(1)
Similarly, OB=OC
⇒ OB2 =OC2
(x + 1)2 + (y + 0)2 = (x + 7)2 + (y - 6)2
⇒ x2 + 1 + 2x + y2 = x2 + 49 - 14x + y2 + 36 +12y
⇒ 16x - 12y - 84 = 0
⇒ 4x - 3y - 21 = 0 .... (2)
⇒ 4x + 12y +24 = 0 .....(1)
on solving (1)& (2) we get,
- 15 y - 45 = 0
⇒ y = -3
from (1)
x - 9 + 6 = 0
⇒ x = 3
Thus coordinate of O are (3 , -3)
Radius =`sqrt ((3 + 2)^2 + (- 3 + 3)^2)`
`= sqrt (25 + 0)`
` = sqrt 25` units
= 5 units
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संबंधित प्रश्न
Prove that the points (0 , 0) , (3 , 2) , (7 , 7) and (4 , 5) are the vertices of a parallelogram.
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The points A (3, 0), B (a, -2) and C (4, -1) are the vertices of triangle ABC right angled at vertex A. Find the value of a.
KM is a straight line of 13 units If K has the coordinate (2, 5) and M has the coordinates (x, – 7) find the possible value of x.
By using the distance formula prove that each of the following sets of points are the vertices of a right angled triangle.
(i) (6, 2), (3, -1) and (- 2, 4)
(ii) (-2, 2), (8, -2) and (-4, -3).
Show that the quadrilateral with vertices (3, 2), (0, 5), (- 3, 2) and (0, -1) is a square.
Find distance between point Q(3, – 7) and point R(3, 3)
Solution: Suppose Q(x1, y1) and point R(x2, y2)
x1 = 3, y1 = – 7 and x2 = 3, y2 = 3
Using distance formula,
d(Q, R) = `sqrt(square)`
∴ d(Q, R) = `sqrt(square - 100)`
∴ d(Q, R) = `sqrt(square)`
∴ d(Q, R) = `square`
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Tharunya was thrilled to know that the football tournament is fixed with a monthly timeframe from 20th July to 20th August 2023 and for the first time in the FIFA Women’s World Cup’s history, two nations host in 10 venues. Her father felt that the game can be better understood if the position of players is represented as points on a coordinate plane. |
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[or]
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