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Let X ~ B(10, 0.2). Find P(X ≤ 8). - Mathematics and Statistics

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प्रश्न

Let X ~ B(10, 0.2). Find P(X ≤ 8).

बेरीज

उत्तर

X ~ B(10, 0.2)

∴ n = 10, p = 0.2

∴ q = 1 - p = 1 - 0.2 = 0.8

The p,m.f. of X is given by

P(X = x) = `"^nC_x  p^x  q^(n - x)`

∴ P(X = x) = `"^10C_x  (0.2)^x  (0.8)^(10 - x)`, x = 0, 1, 2, 3,....,10

P(X ≤ 8) = 1 - P(X > 8)

= 1 - [P(X = 9) + P(X = 10)]

`= 1 - [""^10C_9 (0.2)^9 (0.8)^(10 - 9) + "^10C_10 (0.2)^10 (0.8)^(10-10)]`

`= 1 - [10 (0.2)^9 (0.8)^1 + 1(0.2)^10 (0.8)^0]`

`= 1 - (0.2)^9 [10(0.8) + (0.2)]`

`= 1 - (0.2)^9 [8 + 0.2]`

`= 1 - (8.2)(0.2)^9`

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Binomial Distribution
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पाठ 8: Binomial Distribution - Miscellaneous exercise 2 [पृष्ठ २५३]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] 12 Standard HSC Maharashtra State Board
पाठ 8 Binomial Distribution
Miscellaneous exercise 2 | Q 1.3 | पृष्ठ २५३

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Solution:

A pair of dice is thrown 3 times.

∴ n = 3

Let x = number of success (doublets)

p = probability of success (doublets)

∴  p = `square`, q = `square`

∴ x ∼ B (n, p)

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∴ P(x ≥ 2) = P(x = 2) + P(x = 3)

= `square` + `square`

= `2/27`


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