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Prove that |-a2abacab-b2bcacbc-c2|=4a2b2c2 - Business Mathematics and Statistics

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प्रश्न

Prove that `|(-a^2,ab,ac),(ab,-b^2,bc),(ac,bc,-c^2)| = 4a^2b^2c^2`

बेरीज

उत्तर

`|(-a^2,ab,ac),(ab,-b^2,bc),(ac,bc,-c^2)|`

= `abc|(-a,b,c),(a,-b,c),(a,b,-c)|`   ....(Take out a,b,c respectively from R1, R2 and R3)

= `a^2b^2c^2 |(-1,1,1),(1,-1,1),(1,1,-1)|`   ...(Take out a,b,c respectively from C1, C2 and C3)

= `a^2b^2c^2 |(-1,1,1),(0,0,2),(0,2,0)|`  ...`[("R"_2 -> "R"_2 + "R"_1),("R"_3 -> "R"_3 + "R"_1)]`

= a2b2c2 [-(0 – 4) + 0 + 0]

= 4a2b2c2

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Determinants
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पाठ 1: Matrices and Determinants - Exercise 1.1 [पृष्ठ ८]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 11 TN Board
पाठ 1 Matrices and Determinants
Exercise 1.1 | Q 8. | पृष्ठ ८
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