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प्रश्न
Six boys and six girls sit in a row randomly. The probability that all girls sit together is
पर्याय
1/122
1/112
1/102
1/132
उत्तर
\[\frac{1}{132}\]
Taking all the six girls as one person, seven persons can be seated in a row in 7! ways. The six girls can be arranged among themselves in 6! ways.
Then number of ways in which six boys and six girls can be seated in a row so that all the girls sit together = 7! × 6!
∴ Required probability = \[\frac{7! \times 6!}{\left( 12 \right)!} = \frac{720}{12 \times 11 \times 10 \times 9 \times 8} = \frac{1}{132}\]
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