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प्रश्न
Solve for x:
`3^(4x + 1) = (27)^(x + 1)`
बेरीज
उत्तर
`3^(4x + 1) = (27)^(x + 1)`
⇒ `3^(4x + 1) = (3^3)^(x + 1)`
⇒ `3^(4x + 1) = (3)^(3^((x + 1)))`
⇒ 4x + 1 = 3(x + 1)
⇒ 4x + 1 = 3x + 3
⇒ 4x - 3x = 3 - 1
⇒ x = 2
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Solving Exponential Equations
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