Advertisements
Advertisements
प्रश्न
Solve for x:
`3^(4x + 1) = (27)^(x + 1)`
योग
उत्तर
`3^(4x + 1) = (27)^(x + 1)`
⇒ `3^(4x + 1) = (3^3)^(x + 1)`
⇒ `3^(4x + 1) = (3)^(3^((x + 1)))`
⇒ 4x + 1 = 3(x + 1)
⇒ 4x + 1 = 3x + 3
⇒ 4x - 3x = 3 - 1
⇒ x = 2
shaalaa.com
Solving Exponential Equations
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Find x, if : 42x = `1/32`
Solve for x : `(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`
Solve for x:
`2^(3x + 3) = 2^(3x + 1) + 48`
If m ≠ n and (m + n)-1 (m-1 + n-1) = mxny, show that : x + y + 2 = 0
If `((a^-1b^2 )/(a^2b^-4))^7 ÷ (( a^3b^-5)/(a^-2b^3))^-5 = a^x . b^y` , find x + y.
Evaluate the following:
`(2^3 xx 3^5 xx 24^2)/(12^2 xx 18^3 xx 27)`
Evaluate the following:
`16^(3/4) + 2(1/2)^-1 xx 3^0`
Solve for x:
`9 xx 3^x = (27)^(2x - 5)`
Solve for x:
3 x 7x = 7 x 3x
Find the value of k in each of the following:
`root(4)root(3)(x^2)` = xk