Advertisements
Advertisements
प्रश्न
Solve for x:
`2^(3x + 3) = 2^(3x + 1) + 48`
उत्तर
`2^(3x + 3) = 2^(3x + 1) + 48`
⇒ 23x 23 = 23x21 + 48
⇒ 23x 8 - 23x × 2 = 48
⇒ 23x (8 - 2) = 48
⇒ 23x × 6 = 48
⇒ 23x = `48/6`
⇒ 23x = 8
⇒ 23x = 23
⇒ 3x = 3
⇒ x = `3/3`
⇒ x = 1
APPEARS IN
संबंधित प्रश्न
If 4x + 3 = 112 + 8 × 4x, find the value of (18x)3x.
If 5x + 1 = 25x - 2, find the value of 3x - 3 × 23 - x.
If m ≠ n and (m + n)-1 (m-1 + n-1) = mxny, show that : x + y + 2 = 0
Solve : 3x-1× 52y-3 = 225.
Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`
Solve for x:
9 x 81x = `(1)/(27^(x - 3)`
Solve for x:
`sqrt((3/5)^(x + 3)) = (27^-1)/(125^-1)`
Find the value of k in each of the following:
`(sqrt(9))^-7 xx (sqrt(3))^-5` = 3k
If a = `2^(1/3) - 2^((-1)/3)`, prove that 2a3 + 6a = 3
Prove the following:
`sqrt(x^-1 y) · sqrt(y^-1 z) · sqrt(z^-1 x)` = 1
