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प्रश्न
Solve for x:
`sqrt((3/5)^(x + 3)) = (27^-1)/(125^-1)`
योग
उत्तर
`sqrt((3/5)^(x + 3)) = (27^-1)/(125^-1)`
⇒ `(3/5)^((x+3)xx(1/2)) = ((3^3)^-1)/((5^3)-1)`
⇒ `(3/5)^((x+3)/2) = (3/5)^-3`
⇒ `(x + 3)/(2)` = -3
⇒ x + 3 = -6
⇒ x = -9.
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Solving Exponential Equations
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