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Solve for x: 23x + 3=23x + 1+48 - Mathematics

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Question

Solve for x:

`2^(3x  +  3) = 2^(3x  +  1) + 48`

Sum

Solution

`2^(3x  +  3) = 2^(3x  +  1) + 48`

⇒ 23x 23 = 23x21 + 48

⇒ 23x 8 - 23x × 2 = 48

⇒ 23x (8 - 2) = 48

⇒ 23x × 6  = 48

⇒ 23x = `48/6`

⇒ 23x = 8

⇒ 23x = 23

⇒ 3x = 3

⇒ x = `3/3`

⇒ x = 1

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Solving Exponential Equations
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Chapter 7: Indices (Exponents) - Exercise 7 (B) [Page 101]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 7 Indices (Exponents)
Exercise 7 (B) | Q 14.4 | Page 101
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