Advertisements
Advertisements
प्रश्न
Solve for x:
`2^(3x + 3) = 2^(3x + 1) + 48`
उत्तर
`2^(3x + 3) = 2^(3x + 1) + 48`
⇒ 23x 23 = 23x21 + 48
⇒ 23x 8 - 23x × 2 = 48
⇒ 23x (8 - 2) = 48
⇒ 23x × 6 = 48
⇒ 23x = `48/6`
⇒ 23x = 8
⇒ 23x = 23
⇒ 3x = 3
⇒ x = `3/3`
⇒ x = 1
APPEARS IN
संबंधित प्रश्न
Solve : 22x + 2x+2 - 4 x 23 = 0
Solve for x: `4^(x-1) × (0.5)^(3 - 2x) = (1/8)^-x`
Solve for x : `(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`
If 5x + 1 = 25x - 2, find the value of 3x - 3 × 23 - x.
Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`
Evaluate the following:
`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`
Solve for x:
2x + 3 + 2x + 1 = 320
If a = `2^(1/3) - 2^((-1)/3)`, prove that 2a3 + 6a = 3
If ax = by = cz and b2 = ac, prove that y = `(2xz)/(z + x)`
If 2250 = 2a. 3b. 5c, find a, b and c. Hence, calculate the value of 3a x 2-b x 5-c.
