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Solve for X: 2x + 3 + 2x + 1 = 320 - Mathematics

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प्रश्न

Solve for x:
2x + 3 + 2x + 1 = 320

बेरीज

उत्तर

2x + 3 + 2x + 1 = 320
⇒ 2x + 3 + 2x + 1 = 26 x 5
⇒ 2x . 23 + 2x . 21 = 26 x 5
⇒ 2x (23 + 21) = 26 x 5
⇒ 2x (8 + 2) = 26 x 5
⇒ 2x (10) = 26 x 5
⇒ `2^x (10/5)` = 26
⇒ 2x . 2 = 26
⇒ `(2^x . 2)/(2^6)` = 1
⇒ `2^(x +1 - 6)` = 1 x 20
⇒ `2^(x - 5)` = 1 x 20
⇒ x - 5 = 0
⇒ x = 5.

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Solving Exponential Equations
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पाठ 9: Indices - Exercise 9.1

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फ्रँक Mathematics [English] Class 9 ICSE
पाठ 9 Indices
Exercise 9.1 | Q 9.03
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