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प्रश्न
If a = `2^(1/3) - 2^((-1)/3)`, prove that 2a3 + 6a = 3
उत्तर
a = `2^(1/3) - 2^((-1)/3)`
⇒ a = `2^(1/3) - (1)/(2^(1/3)`
⇒ a3 = `(2^(1/3) - 1/(2^(1/3)))^3`
= `2 - 1/2 - 3(2^(1/3) - 1/(2^(1/3)))`
⇒ a3 = `(4 - 1)/(2) - 3"a"`
⇒ a3 = `(3)/(2) - 3"a"`
⇒ 2a3 + 6a = 3.
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