Advertisements
Advertisements
Question
If a = `2^(1/3) - 2^((-1)/3)`, prove that 2a3 + 6a = 3
Sum
Solution
a = `2^(1/3) - 2^((-1)/3)`
⇒ a = `2^(1/3) - (1)/(2^(1/3)`
⇒ a3 = `(2^(1/3) - 1/(2^(1/3)))^3`
= `2 - 1/2 - 3(2^(1/3) - 1/(2^(1/3)))`
⇒ a3 = `(4 - 1)/(2) - 3"a"`
⇒ a3 = `(3)/(2) - 3"a"`
⇒ 2a3 + 6a = 3.
shaalaa.com
Solving Exponential Equations
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Find x, if : `(root(3)( 2/3))^( x - 1 ) = 27/8`
Solve : 22x + 2x+2 - 4 x 23 = 0
Solve for x : `(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`
Solve for x : 3(2x + 1) - 2x + 2 + 5 = 0
If ax = by = cz and b2 = ac, prove that: y = `[2xz]/[x + z]`
Solve for x:
22x + 2x +2 - 4 x 23 = 0
Solve for x:
9 x 81x = `(1)/(27^(x - 3)`
Solve for x:
9x+4 = 32 x (27)x+1
If x = `3^(2/3) + 3^(1/3)`, prove that x3 - 9x - 12 = 0
Prove the following:
`sqrt(x^-1 y) · sqrt(y^-1 z) · sqrt(z^-1 x)` = 1