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Question
Find the value of k in each of the following:
`(1/3)^-4 ÷ 9^((-1)/(3)` = 3k
Sum
Solution
`(1/3)^-4 ÷ 9^((-1)/(3)` = 3k
⇒ `(3^-1)^-4 ÷ (3^2)^((-1)/(2)` = 3k
⇒ `3^4 ÷ 3^((-2)/(3)` = 3k
⇒ `3^(4 + 2/3)` = 3k
⇒ `3^(14/3)` = 3k
⇒ k = `(14)/(3)`.
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Solving Exponential Equations
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