Advertisements
Advertisements
प्रश्न
Solve for x : 25x-1 = 4 23x + 1
योग
उत्तर
25x-1 = 4 x 23x + 1
⇒ 25x-1 = 22 x 23x + 1
⇒ 25x-1 = 22 + 3x + 1
⇒ 25x-1 = 23x + 3
We know that if bases are equal, the powers are equal
⇒ 5x - 1 = 3x + 3
⇒ 5x - 3x = 3 + 1
⇒ 2x = 4
⇒ x = `4/2`
⇒ x = 2.
shaalaa.com
Solving Exponential Equations
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Find x, if : `( sqrt(3/5))^( x + 1) = 125/27`
Solve : `[3^x]^2` : 3x = 9 : 1
Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`
Solve for x:
2x + 3 + 2x + 1 = 320
Solve for x:
1 = px
Solve for x:
p3 x p-2 = px
Solve for x:
`"p"^-5 = (1)/"p"^(x + 1)`
Solve for x:
9x+4 = 32 x (27)x+1
Find the value of (8p)p if 9p + 2 - 9p = 240.
If `x^(1/3) + y^(1/3) + z^(1/3) = 0`, prove that (x + y + z)3 = 27xyz