Solve for X: P3 X P-2 = Px - Mathematics

Solve for x:
p³ x p^-2 = p^x

योग

p³ x p^-2 = p^x
⇒ `"p"^(3+(-2))` = p^x ......(Using a^m x aⁿ = a^m+n)
⇒ p¹ = p^x
⇒ x = 1.

shaalaa.com

Solving Exponential Equations

क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

अध्याय 9: Indices - Exercise 9.1

अध्याय 9 Indices
Exercise 9.1 | Q 9.07

Find x, if : `( sqrt(3/5))^( x + 1) = 125/27`

Solve for x : (a^{3x + 5})². (a^x)⁴ = a^{8x + 12}

Evaluate : `[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`

Simplify : `[ 3 xx 9^( n + 1 ) - 9 xx 3^(2n)]/[3 xx 3^(2n + 3) - 9^(n + 1 )]`

If `((a^-1b^2 )/(a^2b^-4))^7 ÷ (( a^3b^-5)/(a^-2b^3))^-5 = a^x . b^y` , find x + y.

Solve for x:
2^2x^{- 1} − 9 x 2^{x − 2} + 1 = 0

Find the value of k in each of the following:

`(root(3)(8))^((-1)/(2)` = 2^k

Find the value of (8p)^p if 9^{p + 2} - 9^p = 240.

If 2250 = 2^a. 3^b. 5^c, find a, b and c. Hence, calculate the value of 3^a x 2^-b x 5^-c.

Find the value of 'a' and 'b' if:

`(sqrt243)^"a" ÷ 3^("b" + 1)` = 1 and `27^"b" - 81^(4 -"a"/2)` = 0