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Solve for X: 9 × 3 X = ( 27 ) 2 X − 5 - Mathematics

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प्रश्न

Solve for x:
`9 xx 3^x = (27)^(2x - 5)`

योग

उत्तर

9x 3x = (27)2x- 5
⇒ 32 x 3x = (33)2x- 5
32 x 3x = `3^(3x^((2x - 5))`
⇒ 32+x = 36x-15
⇒ 1 = `(3^(6x - 15))/(3^(2 + x))`
⇒ 1 = `3^(6x - 15 - 2 - x)`
⇒ 30 = 35x-17
⇒ 5x 17 = 0
⇒ x = `(17)/(5)`.

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Solving Exponential Equations
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अध्याय 9: Indices - Exercise 9.1

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 9 Indices
Exercise 9.1 | Q 9.04
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