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प्रश्न
The angles of a triangle are arranged in descending order of their magnitudes. If the difference between two consecutive angles is 10°, find the three angles.
उत्तर
Let one of the angles of a triangle be x. If angles are arranged in descending order. Then, angles will be x, (x – 10°) and (x – 20°).
We know that the sum of all angles in a triangle is equal to 180°
So, x + (x – 10°) + (x – 20°) = 180°
⇒ x + x + x – 30° = 180°
⇒ 3x = 180° + 30°
⇒ 3x = 210°
⇒ x = `210^circ/3` = 70°
Hence, angles will be 70°, 70° – 10° and 70° – 20° i.e., 70°, 60° and 50°.
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