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The area of sector of circle of radius 2cm is ЁЭЬЛcm2. Find the angle contained by the sector.
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Area of sector = ЁЭЬЛ ЁЭСРЁЭСЪ2
Radius of circle = 2ЁЭСРЁЭСЪ
Let ЁЭЬГ = angle subtended by arc at centre
Area of sector =`theta/360^@× pir^2`
=`theta/360^@× pi× 2 × 2`
=`(pitheta)/90^@`
`(pitheta)/90^@`= ЁЭЬЛ ⇒ ЁЭЬГ = 90°
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