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The Equation of the Parabola Whose Focus is (1, −1) and the Directrix is X + Y + 7 = 0 is - Mathematics

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प्रश्न

The equation of the parabola whose focus is (1, −1) and the directrix is x + y + 7 = 0 is

पर्याय

  •  x2 + y2 − 2xy − 18x − 10y = 0 

  •  x2 − 18x − 10y − 45 = 0 

  •  x2 + y2 − 18x − 10y − 45 = 0 

  •  x2 + y2 − 2xy − 18x − 10y − 45 = 0

     
MCQ

उत्तर

x2 + y2 − 2xy − 18x − 10y − 45 = 0 

Let P (xy) be any point on the parabola whose focus is S (1, −1) and the directrix is x + y+ 7 = 0. 

 

Draw PM perpendicular to x + y + 7 = 0.
Then, we have: 

\[SP = PM\]
\[ \Rightarrow S P^2 = P M^2 \]
\[ \Rightarrow \left( x - 1 \right)^2 + \left( y + 1 \right)^2 = \left( \frac{x + y + 7}{\sqrt{1 + 1}} \right)^2 \]
\[ \Rightarrow \left( x - 1 \right)^2 + \left( y + 1 \right)^2 = \left( \frac{x + y + 7}{\sqrt{2}} \right)^2 \]
\[ \Rightarrow 2\left( x^2 + 1 - 2x + y^2 + 1 + 2y \right) = x^2 + y^2 + 49 + 2xy + 14y + 14x\]
\[ \Rightarrow \left( 2 x^2 + 2 - 4x + 2 y^2 + 2 + 4y \right) = x^2 + y^2 + 49 + 2xy + 14y + 14x\]
\[ \Rightarrow x^2 + y^2 - 45 - 10y - 2xy - 18x = 0\] 

Hence, the required equation is x2 + y2 − 2xy − 18x − 10y − 45 = 0. 

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पाठ 25: Parabola - Exercise 25.3 [पृष्ठ ३०]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 25 Parabola
Exercise 25.3 | Q 22 | पृष्ठ ३०

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