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प्रश्न
The hexaquo manganese (II) ion contains five unpaired electrons, while the hexacyanoion contains only one unpaired electron. Explain using Crystal Field Theory.
उत्तर
The configuration of Mn in oxidation state +2 is 3d5. In the presence of H2O (weak field ligand) as ligand, the distribution of these five electrons is \[\ce{t^3_{2{g}} e^2_{{g}}}\] i.e. all the electrons remain unpaired. In the presence of CN– (strong field ligand) as ligand, the distribution is \[\ce{t^5_{2{g}} e^0_{{g}}}\] i.e. two t2g orbitals have paired electrons while the third t2g orbital has one unpaired electron.
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संबंधित प्रश्न
Draw figure to show the splitting of d orbitals in an octahedral crystal field.
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The correct statements are:
The complex that has highest crystal field splitting energy (Δ) is ______.
On the basis of crystal field theory, write the electronic configuration for the d5 ion with a weak ligand for which Δ0 < P.
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On the basis of Crystal Field Theory, write the electronic configuration of d4 ion if Δ0 > P.
