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Question
The hexaquo manganese (II) ion contains five unpaired electrons, while the hexacyanoion contains only one unpaired electron. Explain using Crystal Field Theory.
Solution
The configuration of Mn in oxidation state +2 is 3d5. In the presence of H2O (weak field ligand) as ligand, the distribution of these five electrons is \[\ce{t^3_{2{g}} e^2_{{g}}}\] i.e. all the electrons remain unpaired. In the presence of CN– (strong field ligand) as ligand, the distribution is \[\ce{t^5_{2{g}} e^0_{{g}}}\] i.e. two t2g orbitals have paired electrons while the third t2g orbital has one unpaired electron.
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