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Question
On the basis of crystal field theory explain why Co(III) forms paramagnetic octahedral complex with weak field ligands whereas it forms diamagnetic octahedral complex with strong field ligands.
Solution
With weak field ligands; ∆0 < p, the electronic configuration of Co (III) will be \[\ce{t^4_{2g} e^2_g}\] and it has 4 unpaired electrons and is paramagnetic. With strong field ligands, ∆0 > p, the electronic configuration will be \[\ce{t^6_{2g} e^0_g}\]. It has no unpaired electrons and is diamagnetic.
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The correct statements are:
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